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November 2013
Hello, I'm BracketBot. I have automatically detected that your edit to Maximum flow problem may have broken the syntax by modifying 4 "<>"s. If you have, don't worry: just edit the page again to fix it. If I misunderstood what happened, or if you have any questions, you can leave a message on my operator's talk page.
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 for <math>m\leq O(n^{(16/15)\epsilon})</math> while KRT solve it in ''O''(''VE'') for <math>m > n^{1+\epsilon}</math>
 This problem can be transformed into a maximum flow problem by constructing a network ''N'' = (''X''∪''Y''∪{''s'',''t''}, ''E''<nowiki>' </nowiki>}, where
 't'' ∈ V'' being the source and the sink respectively. We add a game node {''i'',''j''} with ''i'' < ''j'' to ''V'' and connect each of them to ''s'' by an edge and set its capacity to ''r''<sub>i</
 participating in the league and let <math>\scriptstyle r(S  \{k\}) = \sum_{i,j \in \{S\{k\}\}, i < j} r_{ij}</math>. In this method it is claimed team ''k'' is not eliminated if and only if a flow
 't'' ∈ V'' being the source and the sink respectively. We add a game node {''i'',''j''} with ''i'' < ''j'' to ''V'' and connect each of them to ''s'' by an edge and set its capacity to ''r''<sub>i</
 participating in the league and let <math>\scriptstyle r(S  \{k\}) = \sum_{i,j \in \{S\{k\}\}, i < j} r_{ij}</math>. In this method it is claimed team ''k'' is not eliminated if and only if a flow

Thanks, BracketBot (talk) 05:05, 27 November 2013 (UTC)
Hello, I'm BracketBot. I have automatically detected that your edit to Maximum flow problem may have broken the syntax by modifying 1 "[]"s. If you have, don't worry: just edit the page again to fix it. If I misunderstood what happened, or if you have any questions, you can leave a message on my operator's talk page.
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 for <math>m\leq O(n^{(16/15)\epsilon})</math> while KRT solve it in ''O''(''VE'') for <math>m > n^{1+\epsilon}</math>
 This problem can be transformed into a maximum flow problem by constructing a network ''N'' = (''X''∪''Y''∪{''s'',''t''}, ''E''<nowiki>' </nowiki>}, where
 't'' ∈ V'' being the source and the sink respectively. We add a game node {''i'',''j''} with ''i'' < ''j'' to ''V'' and connect each of them to ''s'' by an edge and set its capacity to ''r''<sub>i</
 participating in the league and let <math>\scriptstyle r(S  \{k\}) = \sum_{i,j \in \{S\{k\}\}, i < j} r_{ij}</math>. In this method it is claimed team ''k'' is not eliminated if and only if a flow
 ], ["Possible winners in partially completed tournaments"], ''SIAM Rev., 8'' (1966) 302308]</ref> proposed a method which reduces this problem to maximum network flow. In this method a
 ' ∈ ''V'' being the source and the sink respectively. We add a game node {''i'',''j''} with ''i'' < ''j'' to ''V'' and connect each of them to ''s'' by an edge and set its capacity to ''r''<sub>i</
 participating in the league and let <math>\scriptstyle r(S  \{k\}) = \sum_{i,j \in \{S\{k\}\}, i < j} r_{ij}</math>. In this method it is claimed team ''k'' is not eliminated if and only if a flow

Thanks, BracketBot (talk) 23:53, 27 November 2013 (UTC)
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