# Compact operator

In functional analysis, a branch of mathematics, a compact operator is a linear operator L from a Banach space X to another Banach space Y, such that the image under L of any bounded subset of X is a relatively compact subset of Y. Such an operator is necessarily a bounded operator, and so continuous.

Any bounded operator L that has finite rank is a compact operator; indeed, the class of compact operators is a natural generalisation of the class of finite-rank operators in an infinite-dimensional setting. When Y is a Hilbert space, it is true that any compact operator is a limit of finite-rank operators, so that the class of compact operators can be defined alternatively as the closure in the operator norm of the finite-rank operators. Whether this was true in general for Banach spaces (the approximation property) was an unsolved question for many years; in the end Per Enflo gave a counter-example.

The origin of the theory of compact operators is in the theory of integral equations, where integral operators supply concrete examples of such operators. A typical Fredholm integral equation gives rise to a compact operator K on function spaces; the compactness property is shown by equicontinuity. The method of approximation by finite-rank operators is basic in the numerical solution of such equations. The abstract idea of Fredholm operator is derived from this connection.

## Equivalent formulations

A bounded operator T : X → Y is compact if and only if any of the following is true

Note that if a linear operator is compact, then it is easy to see that it is bounded, and hence continuous.

## Important properties

In the following, X, Y, Z, W are Banach spaces, B(XY) is the space of bounded operators from X to Y with the operator norm, K(XY) is the space of compact operators from X to Y, B(X) = B(XX), K(X) = K(XX), $id_{X}$ is the identity operator on X.

• K(XY) is a closed subspace of B(XY): Let Tn, n ∈ N, be a sequence of compact operators from one Banach space to the other, and suppose that Tn converges to T with respect to the operator norm. Then T is also compact.
• Conversely, if X, Y are Hilbert spaces, then every compact operator from X to Y is the limit of finite rank operators. Notably, this is false for general Banach spaces X and Y.
• An operator is compact if and only if its adjoint is (Schauder's theorem).

## Origins in integral equation theory

A crucial property of compact operators is the Fredholm alternative, which asserts that the existence of solution of linear equations of the form

(where K is a compact operator, f is a given function, and u is the unknown function to be solved for) behaves much like as in finite dimensions. The spectral theory of compact operators then follows, and it is due to Frigyes Riesz (1918). It shows that a compact operator K on an infinite-dimensional Banach space has spectrum that is either a finite subset of C which includes 0, or the spectrum is a countably infinite subset of C which has 0 as its only limit point. Moreover, in either case the non-zero elements of the spectrum are eigenvalues of K with finite multiplicities (so that K − λI has a finite-dimensional kernel for all complex λ ≠ 0).

An important example of a compact operator is compact embedding of Sobolev spaces, which, along with the Gårding inequality and the Lax–Milgram theorem, can be used to convert an elliptic boundary value problem into a Fredholm integral equation. Existence of the solution and spectral properties then follow from the theory of compact operators; in particular, an elliptic boundary value problem on a bounded domain has infinitely many isolated eigenvalues. One consequence is that a solid body can vibrate only at isolated frequencies, given by the eigenvalues, and arbitrarily high vibration frequencies always exist.

The compact operators from a Banach space to itself form a two-sided ideal in the algebra of all bounded operators on the space. Indeed, the compact operators on an infinite-dimensional Hilbert space form a maximal ideal, so the quotient algebra, known as the Calkin algebra, is simple.

## Compact operator on Hilbert spaces

{{#invoke:main|main}} An equivalent definition of compact operators on a Hilbert space may be given as follows.

$T:{\mathcal {H}}\to {\mathcal {H}}$ is said to be compact if it can be written in the form

$T=\sum _{n=1}^{\infty }\lambda _{n}\langle f_{n},\cdot \rangle g_{n}\,,$ where $f_{1},f_{2},\ldots$ and $g_{1},g_{2},\ldots$ are (not necessarily complete) orthonormal sets, and $\lambda _{1},\lambda _{2},\ldots$ is a sequence of positive numbers with limit zero, called the singular values of the operator. The singular values can accumulate only at zero. If the sequence becomes stationary at zero, that is $\lambda _{N+k}=0$ for some $N\in \mathbb {N} ,$ and every  $k=1,2,\dots$ , then the operator has finite rank, i.e, a finite-dimensional range and can be written as

$T=\sum _{n=1}^{N}\lambda _{n}\langle f_{n},\cdot \rangle g_{n}\,.$ The bracket $\langle \cdot ,\cdot \rangle$ is the scalar product on the Hilbert space; the sum on the right hand side converges in the operator norm.

An important subclass of compact operators is the trace-class or nuclear operators.

## Completely continuous operators

Let X and Y be Banach spaces. A bounded linear operator T : XY is called completely continuous if, for every weakly convergent sequence $(x_{n})$ from X, the sequence $(Tx_{n})$ is norm-convergent in Y Template:Harv. Compact operators on a Banach space are always completely continuous. If X is a reflexive Banach space, then every completely continuous operator T : XY is compact.

## Examples

• Every finite rank operator is compact.
• For some fixed g ∈ C([0, 1]; R), define the linear operator T by
$(Tf)(x)=\int _{0}^{x}f(t)g(t)\,\mathrm {d} t.$ That the operator T is indeed compact follows from the Ascoli theorem.
• More generally, if Ω is any domain in Rn and the integral kernel k : Ω × Ω → R is a Hilbert—Schmidt kernel, then the operator T on L2(Ω; R) defined by
$(Tf)(x)=\int _{\Omega }k(x,y)f(y)\,\mathrm {d} y$ is a compact operator.
• By Riesz's lemma, the identity operator is a compact operator if and only if the space is finite-dimensional.