Squashed entanglement: Difference between revisions

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In [[quantum mechanics]], especially [[quantum information]], '''purification''' refers to the fact that every [[Mixed state (physics)|mixed state]] acting on finite dimensional Hilbert spaces can be viewed as the [[partial trace|reduced state]] of some pure state.  
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In purely linear algebraic terms, it can be viewed as a statement about [[positive-semidefinite matrix|positive-semidefinite matrices]].
 
== Statement ==
 
Let ρ be a density matrix acting on a Hilbert space <math>H_A</math> of finite dimension ''n''. Then there exist a Hilbert space <math>H_B</math> and a pure state <math>| \psi \rangle \in H_A \otimes H_B</math> such that the partial trace of <math>| \psi \rangle \langle \psi |</math> with respect to <math>H_B</math>
 
:<math>\operatorname{tr_B} \left( | \psi \rangle \langle \psi | \right )= \rho.</math>
 
We say that <math>| \psi \rangle</math> is the purification of <math>\rho</math>.
 
=== Proof ===
 
A density matrix is by definition positive semidefinite. So ρ can be [[Diagonalizable matrix|diagonalized]] and written as <math>\rho = \sum_{i =1} ^n p_i | i \rangle \langle i |</math> for some basis <math>\{ | i \rangle \}</math>. Let <math>H_B</math> be another copy of the  ''n''-dimensional Hilbert space with any orthonormal basis <math>\{ | i' \rangle \}</math>. Define <math>| \psi \rangle \in H_A \otimes H_B</math> by
 
:<math>| \psi \rangle = \sum_{i} \sqrt{p_i} |i \rangle \otimes | i' \rangle.</math>
 
Direct calculation gives
 
:<math>
\operatorname{tr_B} \left( | \psi \rangle \langle \psi | \right )=
\operatorname{tr_B} \left( \sum_{i, j} \sqrt{p_ip_j} |i \rangle \langle j | \otimes | i' \rangle \langle j'| \right ) = \sum_{i,j} \delta_{i,j} \sqrt{p_i p_j}| i \rangle \langle j | = \rho.
</math>
 
This proves the claim.
 
==== Note ====
 
* The vectorial pure state <math>| \psi \rangle</math> is in the form specified by the [[Schmidt decomposition]].
 
* Since square root decompositions of a positive semidefinite matrix are not unique, neither are purifications.
 
* In linear algebraic terms, a square matrix is positive semidefinite if and only if it can be purified in the above sense. The ''if'' part of the implication follows immediately from the fact that the [[partial trace]] is a [[Choi's theorem on completely positive maps|positive map]].
 
== An application: Stinespring's theorem ==
{{Expand section|date=June 2008}}
By combining [[Choi's theorem on completely positive maps]] and purification of a mixed state, we can recover the [[Stinespring factorization theorem|Stinespring dilation theorem]] for the finite dimensional case.
 
{{DEFAULTSORT:Purification Of Quantum State}}
[[Category:Linear algebra]]
[[Category:Quantum information science]]

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