Runge's phenomenon: Difference between revisions

From formulasearchengine
Jump to navigation Jump to search
en>Lnz.Rossi
No edit summary
en>BG19bot
m →‎Reason: WP:CHECKWIKI error fix for #61. Punctuation goes before References. Do general fixes if a problem exists. - using AWB (10687)
 
Line 1: Line 1:
{{no footnotes|date=February 2013}}
BMI check is actually a rapid strategy to recognize when one's physique mass index is inside, over or beneath the desirable figure. However, the outcome isn't the measure of one's total wellness, it is really a guidebook.<br><br><br><br>Whenever you have a fairly score of twenty to 25 we happen to be observed to be of usual fat. Anything from 25 is overweight and over thirty is obese. Under 20 is deemed to be unhealthy also, considering you may be deemed for being scrawny--that is, harmful light-weight. We probably absence electricity and are in need of muscle.<br><br>In the mid 1800's Belgian scientist Adolphe Quetelet developed the Quetelet index, that is recognized today because the body mass index (BMI). This statistical measuring compares a person's height plus weight plus is a valuable tool to identify fat problems inside a population or for an individual. Though a [http://safedietplans.com/calories-burned-walking calories burned] cannot measure the actual percentage of body fat, its ease of calculation makes it a common diagnostic tool for wellness experts.<br><br>Becoming reasonable inside regard to the total body mass is actually important. Should you recognize that you ought to have to develop a health, then using your BMI because an aid could aid to initiate we off on a great path. Preserve in head despite the reality which you can be healthy plus balanced and have an excessive BMI. If this applies to you, then you may truly well like to converse with a wellness care specialist thus which he or she can facilitate we to select should you desire to make improvements or if your body fat is within simply a healthy variety.<br><br>The BMI of a person is calculated by dividing his/her fat (pounds) by the square of his/her height (inches) and multiplying with 703. This index indicates when a person is underweight, regular, overweight or obese. After is a standard BMI chart for adults.<br><br>For the concern, the actual way of acquiring a BMI is the fact that initially you need to take the fat in kilograms and separate it by the height in meters, squared plus which might be a Body Mass Index. A large amount of people find it quite difficult to calculate their BMI Calculating as it happens to be a deep process plus it can be well calculated with a doctor.<br><br>A low calorie/low nutrition trend diet usually generally contain anywhere from 800 to 1600 calories a day plus will not contain all nutrition you ought to stay healthy. Our bodies are extremely adaptable and will adjust for several days, nevertheless it is very not good to continue with this sort of system over 3 days.
In [[linear algebra]], the '''adjugate''' or '''classical adjoint''' (occasionally referred to as '''adjunct''') of a [[square matrix]] is the [[transpose]] of the [[cofactor matrix]].
 
The adjugate has sometimes been called the "adjoint", but today the "adjoint" of a matrix normally refers to its corresponding [[Hermitian adjoint|adjoint operator]], which is its [[conjugate transpose]].
 
== Definition ==
The adjugate of ''A'' is the [[transpose]] of the [[cofactor matrix]] ''C'' of ''A'':
 
:<math> \mathrm{adj}(\mathbf{A}) = \mathbf{C}^\mathsf{T} </math>.
 
In more detail:  suppose ''R'' is a [[commutative ring]] and '''A''' is an ''n''×''n'' [[matrix (mathematics)|matrix]] with entries from ''R''.
 
* The (''i'',''j'') ''[[minor (linear algebra)|minor]]'' of '''A''', denoted '''A'''<sub>''ij''</sub>, is the [[determinant]] of the (''n''&nbsp;−&nbsp;1)×(''n''&nbsp;−&nbsp;1) matrix that results from deleting row ''i'' and column ''j'' of '''A'''.
 
* The [[Cofactor (linear algebra)#Matrix of cofactors|cofactor matrix]] of '''A''' is the ''n''×''n'' matrix '''C''' whose (''i'',''j'') entry is the (''i'',''j'') ''[[cofactor (linear algebra)|cofactor]]'' of '''A''':
 
::<math>\mathbf{C}_{ij} = (-1)^{i+j} \mathbf{A}_{ij} \,</math>.
 
* The adjugate of '''A''' is the transpose of '''C''', that is, the ''n''×''n'' matrix whose (''i'',''j'') entry is the (''j'',''i'') cofactor of '''A''':
 
::<math>\mathrm{adj}(\mathbf{A})_{ij} = \mathbf{C}_{ji} \,</math>.
 
The adjugate is defined as it is so that the product of A and its adjugate yields a [[diagonal matrix]] whose diagonal entries are det('''A'''):
 
:<math>\mathbf{A} \, \mathrm{adj}(\mathbf{A}) = \det(\mathbf{A}) \, \mathbf{I} \,</math>.
 
'''A''' is invertible if and only if det('''A''') is an invertible element of ''R'', and in that case the equation above yields:
 
:<math>\mathrm{adj}(\mathbf{A}) = \det(\mathbf{A}) \mathbf{A}^{-1} \,</math>,
 
:<math>\mathbf{A}^{-1} = \frac {1} {\det(\mathbf{A})} \, \mathrm{adj}(\mathbf{A}) \,</math>.
 
== Examples ==
 
=== 2 × 2 generic matrix ===
 
The adjugate of the 2&nbsp;×&nbsp;2 matrix
:<math>\mathbf{A} = \begin{pmatrix} {{a}} & {{b}}\\ {{c}}  & {{d}} \end{pmatrix}</math>
is
:<math>\operatorname{adj}(\mathbf{A}) = \begin{pmatrix} \,\,\,{{d}} & \!\!{{-b}}\\ {{-c}} & {{a}} \end{pmatrix}</math>.
It is seen that det(adj('''A''')) = det('''A''') and adj(adj('''A''')) = '''A'''.
 
=== 3 × 3 generic matrix ===
 
Consider the <math>3\times 3</math> matrix
:<math>
\mathbf{A} = \begin{pmatrix}
a_{11} & a_{12} & a_{13} \\
a_{21} & a_{22} & a_{23} \\
a_{31} & a_{32} & a_{33}
\end{pmatrix}
= \begin{pmatrix}
1 & 2 & 3 \\
4 & 5 & 6 \\
7 & 8 & 9
\end{pmatrix}</math>
Its adjugate is the transpose of the cofactor matrix
:<math>
\mathbf{C} = \begin{pmatrix}
+\left| \begin{matrix} a_{22} & a_{23} \\ a_{32} & a_{33}  \end{matrix} \right| &
-\left| \begin{matrix} a_{21} & a_{23} \\ a_{31} & a_{33}  \end{matrix} \right| &
+\left| \begin{matrix} a_{21} & a_{22} \\ a_{31} & a_{32}  \end{matrix} \right| \\
& & \\
-\left| \begin{matrix} a_{12} & a_{13} \\ a_{32} & a_{33} \end{matrix} \right| &
+\left| \begin{matrix} a_{11} & a_{13} \\ a_{31} & a_{33} \end{matrix} \right| &
-\left| \begin{matrix} a_{11} & a_{12} \\ a_{31} & a_{32} \end{matrix} \right| \\
& & \\
+\left| \begin{matrix} a_{12} & a_{13} \\ a_{22} & a_{23} \end{matrix} \right| &
-\left| \begin{matrix} a_{11} & a_{13} \\ a_{21} & a_{23} \end{matrix} \right| &
+\left| \begin{matrix} a_{11} & a_{12} \\ a_{21} & a_{22} \end{matrix} \right|
\end{pmatrix} = \begin{pmatrix}
+\left| \begin{matrix} 5 & 6 \\ 8 & 9 \end{matrix} \right| &
-\left| \begin{matrix} 4 & 6 \\ 7 & 9  \end{matrix} \right| &
+\left| \begin{matrix} 4 & 5 \\ 7 & 8 \end{matrix} \right| \\
& & \\
-\left| \begin{matrix} 2 & 3 \\ 8 & 9 \end{matrix} \right| &
+\left| \begin{matrix} 1 & 3 \\ 7 & 9 \end{matrix} \right| &
-\left| \begin{matrix} 1 & 2 \\ 7 & 8 \end{matrix} \right| \\
& & \\
+\left| \begin{matrix} 2 & 3 \\ 5 & 6 \end{matrix} \right| &
-\left| \begin{matrix}  1 & 3 \\ 4 & 6 \end{matrix} \right| &
+\left| \begin{matrix} 1 & 2 \\ 4 & 5 \end{matrix} \right|
\end{pmatrix}</math>
So that we have
:<math>
\operatorname{adj}(\mathbf{A}) = \begin{pmatrix}
+\left| \begin{matrix} a_{22} & a_{23} \\ a_{32} & a_{33} \end{matrix} \right| &
-\left| \begin{matrix} a_{12} & a_{13} \\ a_{32} & a_{33}  \end{matrix} \right| &
+\left| \begin{matrix} a_{12} & a_{13} \\ a_{22} & a_{23} \end{matrix} \right| \\
& & \\
-\left| \begin{matrix} a_{21} & a_{23} \\ a_{31} & a_{33} \end{matrix} \right| &
+\left| \begin{matrix} a_{11} & a_{13} \\ a_{31} & a_{33} \end{matrix} \right| &
-\left| \begin{matrix} a_{11} & a_{13} \\ a_{21} & a_{23}  \end{matrix} \right| \\
& & \\
+\left| \begin{matrix} a_{21} & a_{22} \\ a_{31} & a_{32} \end{matrix} \right| &
-\left| \begin{matrix} a_{11} & a_{12} \\ a_{31} & a_{32} \end{matrix} \right| &
+\left| \begin{matrix} a_{11} & a_{12} \\ a_{21} & a_{22} \end{matrix} \right|
\end{pmatrix} = \begin{pmatrix}
+\left| \begin{matrix} 5 & 6 \\ 8 & 9 \end{matrix} \right| &
-\left| \begin{matrix} 2 & 3 \\ 8 & 9  \end{matrix} \right| &
+\left| \begin{matrix} 2 & 3 \\ 5 & 6 \end{matrix} \right| \\
& & \\
-\left| \begin{matrix} 4 & 6 \\ 7 & 9 \end{matrix} \right| &
+\left| \begin{matrix} 1 & 3 \\ 7 & 9 \end{matrix} \right| &
-\left| \begin{matrix} 1 & 3 \\ 4 & 6  \end{matrix} \right| \\
& & \\
+\left| \begin{matrix} 4 & 5 \\ 7 & 8 \end{matrix} \right| &
-\left| \begin{matrix} 1 & 2 \\ 7 & 8 \end{matrix} \right| &
+\left| \begin{matrix} 1 & 2 \\ 4 & 5 \end{matrix} \right|
\end{pmatrix}
</math>
where
:<math>\left| \begin{matrix} a_{im} & a_{in} \\ \,\,a_{jm} & a_{jn} \end{matrix} \right|=
\det\left(    \begin{matrix} a_{im} & a_{in} \\ \,\,a_{jm} & a_{jn} \end{matrix} \right)</math>.
 
Therefore '''C''', the matrix of cofactors for '''A''', is
:<math>
\mathbf{C} = \begin{pmatrix}
-3 & 6 & -3 \\
6 & -12 & 6 \\
-3 & 6 & -3
\end{pmatrix}</math>
 
The adjugate is the ''transpose'' of the cofactor matrix. Thus, for instance, the (3,2) entry of the adjugate is the (2,3) cofactor of '''A'''. (In this example, '''C''' happens to be its own transpose, so adj('''A''') = '''C'''.)
 
=== 3 × 3 numeric matrix ===
 
As a specific example, we have
 
:<math>\operatorname{adj}\begin{pmatrix}
\!-3 & \, 2 & \!-5 \\
\!-1 & \, 0 & \!-2 \\
\, 3 & \!-4 & \, 1
\end{pmatrix}=
\begin{pmatrix}
\!-8 &  \,18 &  \!-4 \\
\!-5 &  \!12 &  \,-1 \\
\, 4 &  \!-6 &  \, 2
\end{pmatrix}
</math>.
 
The −6 in the third row, second column of the adjugate was computed as follows:
 
:<math>(-1)^{2+3}\;\operatorname{det}\begin{pmatrix}\!-3&\,2\\ \,3&\!-4\end{pmatrix}=-((-3)(-4)-(3)(2))=-6.</math>
 
Again, the (3,2) entry of the adjugate is the (2,3) cofactor of ''A''. Thus, the submatrix
:<math>\begin{pmatrix}\!-3&\,\!2\\ \,\!3&\!-4\end{pmatrix}</math>
was obtained by deleting the second row and third column of the original matrix '''A'''.
 
== Properties ==
 
The adjugate has the properties
 
:<math>\mathrm{adj}(\mathbf{I}) = \mathbf{I},</math>
:<math>\mathrm{adj}(\mathbf{AB}) = \mathrm{adj}(\mathbf{B})\,\mathrm{adj}(\mathbf{A}),</math>
:<math>\mathrm{adj}(c \mathbf{A}) = c^{n - 1}\mathrm{adj}(\mathbf{A}) </math>
for ''n''×''n'' matrices '''A''' and '''B'''. The second line follows from equations adj('''B''')adj('''A''') =
det('''B''')'''B'''<sup>-1</sup> det('''A''')'''A'''<sup>-1</sup> = det('''AB''')('''AB''')<sup>-1</sup>.
Substituting in the second line '''B''' = '''A'''<sup>m - 1</sup> and performing the recursion, one gets for all integer ''m''
:<math>\mathrm{adj}(\mathbf{A}^{m}) = \mathrm{adj}(\mathbf{A})^{m}.</math>
The adjugate preserves [[transpose|transposition]]:
:<math>\mathrm{adj}(\mathbf{A}^\mathsf{T}) = \mathrm{adj}(\mathbf{A})^\mathsf{T}.</math>
 
Furthermore,
:<math>\det\big(\mathrm{adj}(\mathbf{A})\big) = \det(\mathbf{A})^{n-1}, </math>
:<math>\mathrm{adj}(\mathrm{adj}(\mathbf{A})) = \det(\mathbf{A})^{n - 2}\mathbf{A} </math>
and, if det('''A''') is a unit, then det(adj('''A''')) = det('''A''') and adj(adj('''A''')) = '''A'''.  
 
===Inverses===
As a consequence of [[Laplace expansion|Laplace's formula]] for the determinant of an ''n''×''n'' matrix '''A''', we have
 
:<math>\mathbf{A}\, \mathrm{adj}(\mathbf{A}) = \mathrm{adj}(\mathbf{A})\, \mathbf{A} = \det(\mathbf{A})\, \mathbf I_n \qquad (*)</math>
 
where <math>\mathbf I_n </math> is the ''n''×''n'' [[identity matrix]].  Indeed, the (''i'',''i'') entry of the product '''A'''&nbsp;adj('''A''') is the [[scalar product]] of row ''i'' of '''A''' with row ''i'' of the cofactor matrix '''C''', which is simply the Laplace formula for det('''A''') expanded by row ''i''. Moreover, for ''i'' ≠ ''j'' the (''i'',''j'') entry of the product is the scalar product of row ''i'' of '''A''' with row ''j'' of '''C''', which is the Laplace formula for the determinant of a matrix whose ''i'' and ''j'' rows are equal and is therefore zero.
 
From this formula follows one of the most important results in matrix algebra: A matrix '''A''' over a commutative ring ''R'' is invertible if and only if det('''A''') is invertible in ''R''.
 
For if '''A''' is an [[invertible matrix]] then
 
:<math>1 = \det(\mathbf I_n) = \det(\mathbf{A} \mathbf{A}^{-1}) = \det(\mathbf{A}) \det(\mathbf{A}^{-1}),</math>
 
and equation (*) above shows that
 
:<math>\mathbf{A}^{-1} = \det(\mathbf{A})^{-1}\, \mathrm{adj}(\mathbf{A}).</math>
 
See also [[Cramer's rule]].
 
===Characteristic polynomial===
 
If ''p''(''t'') = det('''A'''&nbsp;−&nbsp;''t''&nbsp;'''I''') is the [[characteristic polynomial]] of '''A''' and we define the polynomial ''q''(''t'') = (''p''(0)&nbsp;−&nbsp;''p''(''t''))/''t'', then
 
:<math> \mathrm{adj}(\mathbf{A}) = q(\mathbf{A}) = -(p_1 \mathbf{I} + p_2 \mathbf{A} + p_3 \mathbf{A}^2 + \cdots + p_{n} \mathbf{A}^{n-1}), </math>
 
where <math> p_j </math> are the coefficients of ''p''(''t''),
 
:<math> p(t) = p_0 + p_1 t + p_2 t^2 + \cdots + p_{n} t^{n}. </math>
 
===Jacobi's formula===
 
The adjugate also appears in [[Jacobi's formula]] for the [[derivative]] of the [[determinant]]:
 
:<math>\frac{\mathrm{d}}{\mathrm{d} \alpha}  \det(A)= \operatorname{tr}\left(\operatorname{adj}(A) \frac{\mathrm{d} A}{\mathrm{d} \alpha}\right).</math>
 
==See also==
 
* [[Trace diagram]]
* [http://mathworld.wolfram.com/Self-Adjoint.html]
 
==References==
{{Reflist}}
 
* {{cite book | last=Strang | first=Gilbert | authorlink=Gilbert Strang | title=Linear Algebra and its Applications | edition=3rd| year=1988 | publisher=Harcourt Brace Jovanovich | isbn=0-15-551005-3 | pages=231–232 | chapter=Section 4.4: Applications of determinants}}
 
==External links==
* [http://www.ee.ic.ac.uk/hp/staff/dmb/matrix/property.html#adjoint Matrix Reference Manual]
*[http://www.elektro-energetika.cz/calculations/matreg.php?language=english Online matrix calculator (determinant, track, inverse, adjoint, transpose)] Compute Adjugate matrix up to order 8
* {{cite web | url=http://www.wolframalpha.com/input/?i=adjugate+of+{+{+a%2C+b%2C+c+}%2C+{+d%2C+e%2C+f+}%2C+{+g%2C+h%2C+i+}+} | title=<nowiki>adjugate of { { a, b, c }, { d, e, f }, { g, h, i } }</nowiki> | work=[[Wolfram Alpha]]}}
 
[[Category:Matrix theory]]
[[Category:Linear algebra]]

Latest revision as of 08:48, 6 January 2015

BMI check is actually a rapid strategy to recognize when one's physique mass index is inside, over or beneath the desirable figure. However, the outcome isn't the measure of one's total wellness, it is really a guidebook.



Whenever you have a fairly score of twenty to 25 we happen to be observed to be of usual fat. Anything from 25 is overweight and over thirty is obese. Under 20 is deemed to be unhealthy also, considering you may be deemed for being scrawny--that is, harmful light-weight. We probably absence electricity and are in need of muscle.

In the mid 1800's Belgian scientist Adolphe Quetelet developed the Quetelet index, that is recognized today because the body mass index (BMI). This statistical measuring compares a person's height plus weight plus is a valuable tool to identify fat problems inside a population or for an individual. Though a calories burned cannot measure the actual percentage of body fat, its ease of calculation makes it a common diagnostic tool for wellness experts.

Becoming reasonable inside regard to the total body mass is actually important. Should you recognize that you ought to have to develop a health, then using your BMI because an aid could aid to initiate we off on a great path. Preserve in head despite the reality which you can be healthy plus balanced and have an excessive BMI. If this applies to you, then you may truly well like to converse with a wellness care specialist thus which he or she can facilitate we to select should you desire to make improvements or if your body fat is within simply a healthy variety.

The BMI of a person is calculated by dividing his/her fat (pounds) by the square of his/her height (inches) and multiplying with 703. This index indicates when a person is underweight, regular, overweight or obese. After is a standard BMI chart for adults.

For the concern, the actual way of acquiring a BMI is the fact that initially you need to take the fat in kilograms and separate it by the height in meters, squared plus which might be a Body Mass Index. A large amount of people find it quite difficult to calculate their BMI Calculating as it happens to be a deep process plus it can be well calculated with a doctor.

A low calorie/low nutrition trend diet usually generally contain anywhere from 800 to 1600 calories a day plus will not contain all nutrition you ought to stay healthy. Our bodies are extremely adaptable and will adjust for several days, nevertheless it is very not good to continue with this sort of system over 3 days.