Representer theorem: Difference between revisions

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The solution to the [[Schrödinger equation]], the [[wavefunction]], describes the quantum mechanical properties of a particle on microscopic scales.  Measurable quantities such as position, momentum and energy are all derived from the wavefunction.<ref name="Davies1">Davies, p. 1</ref> 


<math>\mathrm{i}\hbar\frac{\partial}{\partial t}\psi(x,t) = -\frac{\hbar^2}{2m}\frac{\partial^2}{\partial x^2}\psi(x,t) +V(x)\psi(x,t),</math>
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where <math>\hbar</math> is the [[reduced Planck constant]], <math>m</math> is the [[mass]] of the particle, <math>\mathrm{i}</math> is the [[imaginary unit]] and <math>t</math> is time.
 
One peculiar potential that can be solved exactly is when the electric quadrupole moment is the dominant term of an infinitely long cylinder of charge.
It can be shown that the [[Schrödinger equation]] is solvable for a cylindrically symmetric electric quadrupole, thus indicating that the quadrupole term of an infinitely long cylinder can be quantized.
In the [[physics]] of [[classical electrodynamics]], it can be easily shown that the scalar potential and associated mechanical potential energy of a cylindrically symmetric quadrupole is as follows:
 
:<math>\mathbf{V}_\mathrm{quad} = \frac{\lambda d^2 Cos[2 \phi]}{4 \pi \epsilon_0 s^2}  </math> ([[SI]] units)
:<math>\mathbf{V}_\mathrm{quad} = \frac{Q \lambda d^2 Cos[2 \phi]}{4 \pi \epsilon_0 s^2}  </math> ([[SI]] units)
 
Cylindrical symmetry should be used when solving the equation. The time independent [[Schrödinger equation]] becomes the following in cylindrical symmetry.
 
<math>E \psi(x) = -\frac{\hbar^2}{2m s}\frac{\partial}{\partial s} (s \frac{\partial}{\partial s}) \psi(s,\phi)-\frac{\hbar^2}{2m s^2}\frac{\partial^2}{\partial \phi^2}\psi(s,\phi) +\frac{Q \lambda d^2 Cos[2 \phi]}{4 \pi \epsilon_0 s^2} \psi(s,\phi),</math>
 
Using the technique [[Separation of Variables]], the above equation can be written as two ordinary differential equations in both the radial and azimuthal directions.  The radial equation is [[Bessel's equation]] as can be seen below. If one changes variables to <math>x= k s</math>, Bessel's equation is exactly obtained.
 
<math>\frac{1}{x} \frac{\partial}{\partial x} (x \frac{\partial}{\partial x}) S(x)+(1-\frac{\nu^2}{x^2}) S(x)=0</math>
 
==Azimuthal equation==
The azimuthal equation is [[Mathieu equation]], is as follows:
 
<math> \frac{\partial^2}{\partial \phi^2} \Phi(\phi)+(\nu^2-\frac{\lambda q m d^2}{2 \pi \epsilon_0 \hbar} Cos[2 \phi]) \Phi[\phi]=0</math>
 
Since the canonical form of Mathieu's equation can be written as follows, it can be shown that <math>\nu^2</math> corresponds to a and <math>\frac{\lambda q m d^2}{2 \pi \epsilon_0 \hbar} </math> corresponds to q.
 
:<math> \frac{d^2y}{dx^2}+[a-2q\cos (2x) ]y=0. </math>
 
The solution of the [[Mathieu equation]] is expressed in terms of '''Mathieu cosine''' <math>C(a,q,x)</math> '''Mathieu sine''' <math>S(a,q,x)</math> for a unique a and q. This indicates that the quadrupole moment can be quantized in order of the Mathieu characteristic values <math>a_n</math> and <math>b_n</math>.
 
In general, Mathieu functions are not periodic. The term q must be that of a characteristic value in order for Mathieu functions to be periodic.  Immediately, it can be shown that the solution of the radial equation highly depends on what characteristic values are seen in this case.
 
== References ==
{{reflist}}
 
==External links==
* [[Cylindrical multipole moments|- Cylindrical Multipole Moments]]
* [http://www.jpier.org/PIERB/pierb26/09.10063008.pdf MULTIPOLE EXPANSION]
* [http://www.sciencedirect.com/science/article/pii/0022285268900027 The nonvanishing coefficients of the dipole moment expansion in axially symmetric molecules]
 
[[Category:Quantum mechanics]]

Latest revision as of 19:40, 16 October 2014


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