Farey sequence

From formulasearchengine
Revision as of 17:41, 31 January 2014 by en>Rtomas (Applications: - continuing)
Jump to navigation Jump to search

The Laplace transform is a powerful integral transform used to switch a function from the time domain to the s-domain. The Laplace transform can be used in some cases to solve linear differential equations with given initial conditions.

First consider the following property of the Laplace transform:

{f}=s{f}f(0)
{f}=s2{f}sf(0)f(0)

One by induction can prove that

{f(n)}=sn{f}i=1nsnif(i1)(0)

Now we consider the following differential equation:

i=0naif(i)(t)=ϕ(t)

with given initial conditions

f(i)(0)=ci

Using the linearity of the Laplace transform it is equivalent to rewrite the equation as

i=0nai{f(i)(t)}={ϕ(t)}

obtaining

{f(t)}i=0naisii=1nj=1iaisijf(j1)(0)={ϕ(t)}

Solving the equation for {f(t)} and substituting f(i)(0) with ci one obtains

{f(t)}={ϕ(t)}+i=1nj=1iaisijcj1i=0naisi

The solution for f(t) is obtained by applying the inverse Laplace transform to {f(t)}.

Note that if the initial conditions are all zero, i.e.

f(i)(0)=ci=0i{0,1,2,...n}

then the formula simplifies to

f(t)=1{{ϕ(t)}i=0naisi}

An example

We want to solve

f(t)+4f(t)=sin(2t)

with initial conditions f(0) = 0 and f′(0)=0.

We note that

ϕ(t)=sin(2t)

and we get

{ϕ(t)}=2s2+4

The equation is then equivalent to

s2{f(t)}sf(0)f(0)+4{f(t)}={ϕ(t)}

We deduce

{f(t)}=2(s2+4)2

Now we apply the Laplace inverse transform to get

f(t)=18sin(2t)t4cos(2t)

Bibliography

  • A. D. Polyanin, Handbook of Linear Partial Differential Equations for Engineers and Scientists, Chapman & Hall/CRC Press, Boca Raton, 2002. ISBN 1-58488-299-9