Abelian integral

The Cartan decomposition is a decomposition of a semisimple Lie group or Lie algebra, which plays an important role in their structure theory and representation theory. It generalizes the polar decomposition or singular value decomposition of matrices. Its history can be traced to the 1880s work of Élie Cartan and Wilhelm Killing. [1]

Cartan involutions on Lie algebras

Let $\mathfrak{g}$ be a real semisimple Lie algebra and let $B(\cdot ,\cdot )$ be its Killing form. An involution on $\mathfrak{g}$ is a Lie algebra automorphism $\theta$ of $\mathfrak{g}$ whose square is equal to the identity. Such an involution is called a Cartan involution on $\mathfrak{g}$ if $B_{\theta }(X,Y):=-B(X,\theta Y)$ is a positive definite bilinear form.

Two involutions ${\theta }_1$ and ${\theta }_2$ are considered equivalent if they differ only by an inner automorphism.

Any real semisimple Lie algebra has a Cartan involution, and any two Cartan involutions are equivalent.

Examples

• A Cartan involution on ${\mathfrak{s}\mathfrak{l}}_n(\mathbb{ℝ})$ is defined by $\theta (X)=-X^T$, where $X^T$ denotes the transpose matrix of $X$.
• The identity map on $\mathfrak{g}$ is an involution, of course. It is the unique Cartan involution of $\mathfrak{g}$ if and only if the Killing form of $\mathfrak{g}$ is negative definite. Equivalently, $\mathfrak{g}$ is the Lie algebra of a compact semisimple Lie group.
• Let $\mathfrak{g}$ be the complexification of a real semisimple Lie algebra ${\mathfrak{g}}_0$, then complex conjugation on $\mathfrak{g}$ is an involution on $\mathfrak{g}$. This is the Cartan involution on $\mathfrak{g}$ if and only if ${\mathfrak{g}}_0$ is the Lie algebra of a compact Lie group.
• The following maps are involutions of the Lie algebra $\mathfrak{s}\mathfrak{u}(n)$ of the special unitary group SU(n):
  • the identity involution ${\theta }_0(X)=X$, which is the unique Cartan involution in this case;
  • ${\theta }_1(X)=-X^T$ which on $\mathfrak{s}\mathfrak{u}(n)$ is also the complex conjugation;
  • if $n=p+q$ is odd, ${\theta }_2(X)=\left(\begin{array}{cc}{I}_p& 0\\ 0& -I_q\end{array}\right)X\left(\begin{array}{cc}{I}_p& 0\\ 0& -I_q\end{array}\right)$. These are all equivalent, but not equivalent to the identity involution (because the matrix $\left(\begin{array}{cc}{I}_p& 0\\ 0& -I_q\end{array}\right)$ does not belong to $\mathfrak{s}\mathfrak{u}(n)$.)
  • if $n=2m$ is even, we also have ${\theta }_3(X)=\left(\begin{array}{cc}0& I_m\\ -I_m& 0\end{array}\right)X^T\left(\begin{array}{cc}0& I_m\\ -I_m& 0\end{array}\right).$

Cartan pairs

Let $\theta$ be an involution on a Lie algebra $\mathfrak{g}$. Since ${\theta }^2=1$, the linear map $\theta$ has the two eigenvalues $\pm 1$. Let $\mathfrak{k}$ and $\mathfrak{p}$ be the corresponding eigenspaces, then $\mathfrak{g}=\mathfrak{k}+\mathfrak{p}$. Since $\theta$ is a Lie algebra automorphism, eigenvalues are multiplicative. It follows that

$[\mathfrak{k},\mathfrak{k}]\subseteq \mathfrak{k}$, $[\mathfrak{k},\mathfrak{p}]\subseteq \mathfrak{p}$, and $[\mathfrak{p},\mathfrak{p}]\subseteq \mathfrak{k}$.

Thus $\mathfrak{k}$ is a Lie subalgebra, while any subalgebra of $\mathfrak{p}$ is commutative.

Conversely, a decomposition $\mathfrak{g}=\mathfrak{k}+\mathfrak{p}$ with these extra properties determines an involution $\theta$ on $\mathfrak{g}$ that is $+1$ on $\mathfrak{k}$ and $-1$ on $\mathfrak{p}$.

Such a pair $(\mathfrak{k},\mathfrak{p})$ is also called a Cartan pair of $\mathfrak{g}$.

The decomposition $\mathfrak{g}=\mathfrak{k}+\mathfrak{p}$ associated to a Cartan involution is called a Cartan decomposition of $\mathfrak{g}$. The special feature of a Cartan decomposition is that the Killing form is negative definite on $\mathfrak{k}$ and positive definite on $\mathfrak{p}$. Furthermore, $\mathfrak{k}$ and $\mathfrak{p}$ are orthogonal complements of each other with respect to the Killing form on $\mathfrak{g}$.

Cartan decomposition on the Lie group level

Let $G$ be a semisimple Lie group and $\mathfrak{g}$ its Lie algebra. Let $\theta$ be a Cartan involution on $\mathfrak{g}$ and let $(\mathfrak{k},\mathfrak{p})$ be the resulting Cartan pair. Let $K$ be the analytic subgroup of $G$ with Lie algebra $\mathfrak{k}$. Then:

• There is a Lie group automorphism $\mathrm{\Theta }$ with differential $\theta$ that satisfies ${\mathrm{\Theta }}^2=1$.
• The subgroup of elements fixed by $\mathrm{\Theta }$ is $K$; in particular, $K$ is a closed subgroup.
• The mapping $K\times \mathfrak{p}\to G$ given by $(k,X)\mapsto k\cdot \mathrm{e}\mathrm{x}\mathrm{p}(X)$ is a diffeomorphism.
• The subgroup $K$ contains the center $Z$ of $G$, and $K$ is compact modulo center, that is, $K/Z$ is compact.
• The subgroup $K$ is the maximal subgroup of $G$ that contains the center and is compact modulo center.

The automorphism $\mathrm{\Theta }$ is also called global Cartan involution, and the diffeomorphism $K\times \mathfrak{p}\to G$ is called global Cartan decomposition.

For the general linear group, we get $X\mapsto (X^{-1}{)}^T$ as the Cartan involution.

A refinement of the Cartan decomposition for symmetric spaces of compact or noncompact type states that the maximal Abelian subalgebras $\mathfrak{a}$ in $\mathfrak{p}$ are unique up to conjugation by K. Moreover

$\mathfrak{p}=\bigcup _{k\in K}\mathrm{A}\mathrm{d}k\cdot \mathfrak{a}.$

In the compact and noncompact case this Lie algebraic result implies the decomposition

$G=KAK,$

where A = exp $\mathfrak{a}$. Geometrically the image of the subgroup A in G / K ia a totally geodesic submanifold.

Relation to polar decomposition

Consider ${\mathfrak{g}\mathfrak{l}}_n(\mathbb{ℝ})$ with the Cartan involution $\theta (X)=-X^T$. Then $\mathfrak{k}={\mathfrak{s}\mathfrak{o}}_n(\mathbb{ℝ})$ is the real Lie algebra of skew-symmetric matrices, so that $K=\mathrm{S}\mathrm{O}(n)$, while $\mathfrak{p}$ is the subspace of symmetric matrices. Thus the exponential map is a diffeomorphism from $\mathfrak{p}$ onto the space of positive definite matrices. Up to this exponential map, the global Cartan decomposition is the polar decomposition of a matrix. Notice that the polar decomposition of an invertible matrix is unique.

See also

• Lie group decompositions

References

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• A. W. Knapp, Lie groups beyond an introduction, ISBN 0-8176-4259-5, Birkhäuser.