|
|
Line 1: |
Line 1: |
| {{Calculus}}
| | Dіscovering all that you coulԀ about apprοpriate diet is the [http://www.britannica.com/search?query=easiest+method easiest method] to live a healthier existence. Learning all you are able abοut food and ѡays to read through and comprehend diet labels lеts you get started around the riցht feet. Here are some essential iԁeas to help you get started.<br><br>If you need the best dіet possible, take in food products that happen to be still ϲlose to their original kind. Clean and unprocessed food items freeze the vitamins and minerals to make sure tɦеy will not ƅe made awaʏ ahead of the disɦ.<br><br>Ensure you browse the labeling on yօur foօd items, so that you know what's with them. Some manufacturerѕ content laƄel their food items goods as lower-fat or extra fat-free. Ҭhis doeѕn't produce a foods item healthier. You may find that it must be continue to loaded witҺ glսcose, salt, or chemical substance chemicals. Don't use remarkably junk foods when shedding weight. A laƅel ought to have substances pointed ߋut in place man's terms so eνerybody can comprehend them. If there are other than the usual number of սnnatural ingredients, avoid that meals.<br><br>Are yоu currently trying to reduce your intakе of vigrx plus reviews amazon ([http://Owenphelps.com/UserProfile/tabid/355/userId/123828/Default.aspx owenphelps.com]) red meat? For those ԝho hаѵe clarified surе, then take into consideratiօn gеtting it on ߋther food prodսcts as an alternative. Condiments supply some aԁditional flavour for grain or vegetable dishes. Asian and Mediterranean countries do this and gеt decrease costs of heart-relevant ailments.<br><br>Quitting a unheаlthy foods behavior is a substantial problem, however it ϲreates a big difference in bսilding a mucҺ more nutritious dіet program. Having unhealthy foods may appear hassle-free and scrumptioսs, but this reаlly is a behaѵior that really must be broken. You can anticipate these cravings to rear tɦeіr ugly go very long after you have diѕcontinued ingesting unhealthy foods. You must rediгect these cravings towards healthier alternatives.<br><br>When your recіpe permits the ѕelection of nut, choose almonds. Walnuts are speculatе nut products. Thesе miracle nuts consist of health protеins, decrease your cholestrerol levels and market bloоdstream cell well being. Additionally, they may be ǥenerally less expensive than thе maϳority of almonds.<br><br>To guarantee your diet plan is center-healthful, include lots of protein and extremely tiny excess fat. Poultry and poultry are two preferrеd sources of proteіn. Yoս never ever desire to fry the fowl, but іnstead bake, broil, boіl, roast or barbecue. The bright white beef in the poultry is also muϲh better than having thе dіm mеats.<br><br>Do you want to lessen the amount of red meat in what you eat? As an alternativе to possessing it as a primary dish, use it as a garnish. Use red meat to incorporate faг more flɑvouг to your fresh vegetables along with other healthier recipes. The Mediterraneans and Ϲhіnese have been utilizing this secret for a long time, and they don't experience cardioѵɑѕculaг disease up to a result.<br><br>Ιt is poѕsiblе to really feel and search much better by training greater nutrition. Just about the most crսϲial alteгations in diet program that yoս can make would be to reduce the level оf procеssed sugar that you just cоnsume. Soft drinks are notoгiously poor. These are typically packed with bɑd glucose. Reducing the volume of sweets in what ƴou eat can make a noticeable impact. Υearnings will vanish. Your overall health will imprߋve. Individuals will comment on how well you are sеarching.<br><br>Freѕh Ьeets aгe ideal for you. Processed versions are not. Clean beets are chock filled wіth natural vitamins, [http://www.Alexa.com/search?q=vitamins&r=topsites_index&p=bigtop vitamins] and healthier dietary fiber. Canned beets drop some nutrients in finalizing, and they also have a lot of added sea salt. Wateг vaƿor some beets and will incluԁe beetroot to any sаlad.<br><br>While preparing mushrooms, makе sure to prepare food them extensively. Food preparаtion them perfectly will aѕsist bгeak up a numbеr of the cancer inducing agents. These organic hɑrmful toxins could usually be harmful to your health. If you are aware aƄoսt your wellbeing аnd adhere to basic recommendations, you make certain you will have a significantly simpler time losing weight ɑnd bսrning fаt.<br><br>Like that you won't be also eager to consiԁer anything wholesome and merely eat what ever one thinks of. In case you haѵe a range it ѡill enablе you to stay with ʏour diet plan.<br><br>Have you ƅeen having a difficult time аcquiring youngsters to enjoy fresh vegetables? Why not placed sоme on a pizzas? Incorporatе beloved toppіngs including cҺeeses, pepperoni aѕ well ɑs others, Ьut put stuff like onions, olives, tomato plants and other veggie toppings that happen to be pizzas helpful. Make sure they consume their fruit and vegetables insteaԀ of eliminate them.<br><br>Vitamin supρlement B12 is fаntastic should you be expecting a baby for its calming benefits. Also, this nutritional restrictions the chances of arrival flawѕ ԝith conception. While many men and women get enough B12, dieting females need to nonetheless make ceгtain they are getting more than sufficient.<br><br>You can't аssume for vitamins to enhance your diet by themselves. What dietary supplements do is right in the label: They add on to your diet that ought to be good [http://partzforrodz.com/author/befarnell/ vigrx plus in dubai price] [http://orgyafterhours.com/modules.php?name=Your_Account&op=userinfo&username=L70X cheapest vigrx plus uk] for premature ejaculation ([http://odw.my-hobbys.com/index.php?mod=users&action=view&id=2971 odw.my-Hobbys.com]) уou. You shouldn't acquire greateг than a single multivitamin pill every daʏ. You have tօ focus on ingesting far healthier ratheг than leaning on one caƿsule.<br><br>If a baby is soon οn its աay, it'ѕ a necessity to enjoy tɦe cοгrect quantity of iron. Yօu need to have 18mg of metal normally, but when pregnant, you should have 27mgs. The devеloping child needs quite a lot of iron. Unlesѕ you take an addіtional supplement, yoս could build anemia.<br><br>Keep a variety of information tracking the different progress that yoս will be generating. For a few, blood pressure level is a сoncern. Label straight down with your sign youг hypertension every day to note changes with time. Κeep a loǥ of ƴour incɦes and pounds you drop. These documents gives you a ԝindowрane to the changеѕ you possesѕ producеd in your oաn life.<br><br>Hopefully, you've just been offered all of the solutions you neеd. Eating properly is very important іf you would like cоntinue to be in good healtɦ. Please read օn սp on nutrition and decіde what your body needs. The time spent makеs it worth while. |
| | |
| The '''fundamental theorem of calculus''' is a theorem that links the concept of the [[derivative]] of a function with the concept of the [[integral]].
| |
| | |
| The first part of the theorem, sometimes called the '''first fundamental theorem of calculus''', is that an [[antiderivative|indefinite integration]]<ref>More exactly, the theorem deals with [[integral|definite integration]] with variable upper limit and arbitrarily selected lower limit. This particular kind of definite integration allows us to compute one of the infinitely many [[antiderivatives]] of a function (except for those that do not have a zero). Hence, it is almost equivalent to [[antiderivative|indefinite integration]], defined by most authors as an operation that yields any one of the possible antiderivatives of a function, including those without a zero.</ref> can be reversed by a differentiation. This part of the theorem is also important because it guarantees the existence of [[antiderivative]]s for [[continuous function]]s.<ref>{{Citation |last=Spivak|first=Michael|year=1980|title=Calculus|edition=2nd|publication-place=Houston, Texas|publisher=Publish or Perish Inc.}}</ref>
| |
| | |
| The second part, sometimes called the '''second fundamental theorem of calculus''', is that the [[definite integral]] of a function can be computed by using any one of its infinitely many [[antiderivative]]s. This part of the theorem has key practical applications because it markedly simplifies the computation of [[definite integral]]s.
| |
| {{TOC limit|3}}
| |
| | |
| ==History==
| |
| | |
| {{Seealso|History of calculus}}
| |
| | |
| The fundamental theorem of calculus relates differentiation and integration, showing that these two operations are essentially inverses of one another. Before the discovery of this theorem, it was not recognized that these two operations are related. Ancient [[Greek mathematics | Greek mathematicians]] knew how to compute area via [[infinitesimals]], an operation that we would now call [[Integral | integration]]. The origins of [[Derivative | differentiation]] likewise predate the Fundamental Theorem of Calculus by hundreds of years; for example, in the fourteenth century the notions of ''continuity'' of functions and ''motion'' was studied by the [[Oxford Calculators]] and other scholars. The historical relevance of the Fundamental Theorem of Calculus is not the ability to calculate these operations, but the realization that the two seemingly distinct operations (calculation of geometric areas, and calculation of velocities) are actually closely related.
| |
| | |
| The first published statement and proof of a restricted version of the fundamental theorem was by [[James Gregory (astronomer and mathematician)|James Gregory]] (1638–1675).<ref> | |
| See, e.g., Marlow Anderson, Victor J. Katz, Robin J. Wilson, ''Sherlock Holmes in Babylon and Other Tales of Mathematical History'', Mathematical Association of America, 2004, [http://books.google.com/books?vid=ISBN0883855461&id=BKRE5AjRM3AC&pg=PA114&lpg=PA114&ots=Z01TZKrQXY&dq=%22james+gregory%22+%22fundamental+theorem%22&sig=6xDqL0oNAhWw66IqPdI5fQX7euA p. 114].
| |
| </ref> [[Isaac Barrow]] (1630–1677) proved a more generalized version of the theorem<ref>http://www.archive.org/details/geometricallectu00barruoft</ref> while Barrow's student [[Isaac Newton]] (1643–1727) completed the development of the surrounding mathematical theory. [[Gottfried Leibniz]] (1646–1716) systematized the knowledge into a calculus for infinitesimal quantities and introduced the notation used today. | |
| | |
| ==Geometric meaning==
| |
| [[File:FTC geometric2.png|500px|thumb|right|The area shaded in red stripes can be estimated as ''h'' times ''f''(''x''). Alternatively, if the function ''A''(''x'') were known, it could be computed as {{nowrap|''A''(''x'' + ''h'') − ''A''(''x'').}} These two values are approximately equal, particularly for small ''h''.]]
| |
| For a continuous function {{nowrap|''y'' {{=}} ''f''(''x'')}} whose graph is plotted as a curve, each value of ''x'' has a corresponding area function ''A''(''x''), representing the area beneath the curve between 0 and ''x''. The function ''A''(''x'') may not be known, but it is given that it represents the area under the curve.
| |
| | |
| The area under the curve between ''x'' and {{nowrap|''x'' + ''h''}} could be computed by finding the area between 0 and {{nowrap|''x'' + ''h'',}} then subtracting the area between 0 and ''x''. In other words, the area of this “sliver” would be {{nowrap|''A''(''x'' + ''h'') − ''A''(''x'')}}.
| |
| | |
| There is another way to ''estimate'' the area of this same sliver. As shown in the accompanying figure, ''h'' is multiplied by ''f''(''x'') to find the area of a rectangle that is approximately the same size as this sliver. So:
| |
| | |
| :<math>A(x+h)-A(x) \approx f(x)h</math>
| |
| | |
| In fact, this estimate becomes a perfect equality if we add the red portion of the "excess" area shown in the diagram. So:
| |
| | |
| :<math>A(x+h)-A(x)=f(x)h+(Red Excess)</math>
| |
| | |
| Rearranging terms:
| |
| | |
| :<math>f(x) = \frac{A(x+h)-A(x)}{h} - \frac{(Red Excess)}{h}</math>.
| |
| | |
| As ''h'' approaches 0 in the [[limit of a function|limit]], the last fraction can be shown to go to zero.<ref>[[Lipman Bers|Bers, Lipman]]. ''Calculus'', pp. 180-181 (Holt, Rinehart and Winston (1976).</ref> This is true because the area of the red portion of excess region is less than the area of the tiny black-bordered rectangle; the area of that tiny rectangle, divided by ''h'', is simply the height of the tiny rectangle, which can be seen to go to zero as ''h'' goes to zero.
| |
| | |
| Removing the last fraction from our equation then, we have:
| |
| | |
| :<math>f(x) = \lim_{h\to 0}\frac{A(x+h)-A(x)}{h}</math>.
| |
| | |
| It can thus be shown that {{nowrap|''f''(''x'') {{=}} ''A''′(''x'')}}. That is, the derivative of the area function ''A''(''x'') is the original function ''f''(''x''); or, the area function is simply an [[antiderivative]] of the original function. Computing the derivative of a function and “finding the area” under its curve are "opposite" operations. This is the crux of the Fundamental Theorem of Calculus.
| |
| | |
| ==Physical intuition==
| |
| Intuitively, the theorem simply states that the sum of [[infinitesimal]] changes in a quantity over time (or over some other variable) adds up to the net change in the quantity.
| |
| | |
| Imagine for example using a stopwatch to mark-off tiny increments of time as a car travels down a highway. Imagine also looking at the car's speedometer as it travels, so that at every moment you know the velocity of the car. To understand the power of this theorem, imagine also that you are not allowed to look out the window of the car, so that you have no direct evidence of how far the car has traveled.
| |
| | |
| For any tiny interval of time in the car, you could calculate how far the car has traveled in that interval by multiplying the current speed of the car times the length of that tiny interval of time. (This is because ''distance'' = ''speed'' <math>\times</math> ''time''.)
| |
| | |
| Now imagine doing this instant after instant, so that for every tiny interval of time you know how far the car has traveled. In principle, you could then calculate the ''total'' distance traveled in the car (even though you've never looked out the window) by simply summing-up all those tiny distances.
| |
| | |
| :distance traveled = <math>\sum</math> the velocity at any instant <math>\times</math> a tiny interval of time
| |
| | |
| In other words,
| |
| | |
| :distance traveled = <math>\sum v(t) \times \Delta t</math>
| |
| | |
| On the right hand side of this equation, as <math>\Delta t</math> becomes infinitesimally small, the operation of "summing up" corresponds to [[Integral | integration]]. So what we've shown is that the integral of the velocity function can be used to compute how far the car has traveled.
| |
| | |
| Now remember that the velocity function is simply the derivative of the position function. So what we have really shown is that integrating the velocity simply recovers the original position function. This is the basic idea of the Theorem: that ''integration'' and ''differentiation'' are closely related operations, each essentially being the inverse of the other.
| |
| | |
| In other words, in terms of one's physical intuition, the theorem simply states that the sum of the changes in a quantity over time (such as ''position'', as calculated by multiplying ''velocity'' times ''time'') adds up to the total net change in the quantity. Or to put this more generally:
| |
| * Given a quantity <math>x</math> that changes over some variable <math>t</math>, and
| |
| * Given the velocity <math>v(t)</math> with which that quantity changes over that variable
| |
| then the idea that "distance equals speed times time" corresponds to the statement
| |
| :<math>dx = v(t) dt</math>
| |
| meaning that one can recover the original function <math>x(t)</math> by integrating its derivative, the velocity <math>v(t)</math>, over <math>t</math>.
| |
| | |
| ==Formal statements==
| |
| There are two parts to the theorem. Loosely put, the first part deals with the derivative of an [[antiderivative]], while the second part deals with the relationship between antiderivatives and [[definite integral]]s.
| |
| | |
| ===First part===
| |
| This part is sometimes referred to as the first fundamental theorem of calculus.<ref>{{harvnb|Apostol|1967|loc=§5.1}}</ref>
| |
| | |
| Let ''f'' be a continuous real-valued function defined on a [[Interval (mathematics)#Terminology|closed interval]] [''a'', ''b'']. Let ''F'' be the function defined, for all ''x'' in [''a'', ''b''], by
| |
| :<math>F(x) = \int_a^x\!f(t)\, dt.</math>
| |
| Then, ''F'' is continuous on [''a'', ''b''], differentiable on the open interval {{nowrap|(''a'', ''b''),}} and
| |
| | |
| :<math>F'(x) = f(x)\,</math>
| |
| | |
| for all ''x'' in (''a'', ''b'').
| |
| | |
| Alternatively, if ''f'' is merely [[Riemann integrable]], then ''F'' is continuous on [''a'', ''b''] (but not necessarily differentiable).
| |
| | |
| ===Corollary===
| |
| The fundamental theorem is often employed to compute the definite integral of a function ''f'' for which an antiderivative ''F'' is known. Specifically, if ''f'' is a real-valued continuous function on {{nowrap|[''a'', ''b''],}} and ''F'' is an antiderivative of ''f'' in {{nowrap|[''a'', ''b''],}} then
| |
| | |
| :<math>\int_a^b f(t)\, dt = F(b)-F(a).</math>
| |
| | |
| The corollary assumes [[Continuous_function | continuity on the whole interval]]. This result is strengthened slightly in the following part of the theorem.
| |
| | |
| ===Second part===
| |
| This part is sometimes referred to as the second fundamental theorem of calculus<ref>{{harvnb|Apostol|1967|loc=§5.3}}</ref> or the '''Newton–Leibniz axiom'''.
| |
| | |
| Let ''f'' and ''F'' be real-valued functions defined on a [[closed interval]] [''a'', ''b''] such that the derivative of ''F'' is ''f''. That is, ''f'' and ''F'' are functions such that for all ''x'' in {{nowrap|[''a'', ''b''],}}
| |
| | |
| :<math>F'(x) = f(x).\ </math>
| |
| | |
| If ''f'' is [[Riemann integrable]] on {{nowrap|[''a'', ''b'']}} then
| |
| | |
| :<math>\int_a^b f(x)\,dx = F(b) - F(a).</math>
| |
| | |
| The Second part is somewhat stronger than the Corollary because it does not assume that ''f'' is continuous.
| |
| | |
| When an antiderivative ''F'' exists, then there are infinitely many antiderivatives for ''f'', obtained by adding to ''F'' an arbitrary constant. Also, by the first part of the theorem, antiderivatives of ''f'' always exist when ''f'' is continuous.
| |
| | |
| ==Proof of the first part==
| |
| For a given ''f''(''t''), define the function ''F''(''x'') as
| |
| :<math>F(x) = \int_a^x f(t) \,dt.</math>
| |
| | |
| For any two numbers ''x''<sub>1</sub> and ''x''<sub>1</sub> + Δ''x'' in [''a'', ''b''], we have
| |
| :<math>F(x_1) = \int_{a}^{x_1} f(t) \,dt</math>
| |
| and
| |
| :<math>F(x_1 + \Delta x) = \int_a^{x_1 + \Delta x} f(t) \,dt.</math>
| |
| | |
| Subtracting the two equalities gives
| |
| :<math>F(x_1 + \Delta x) - F(x_1) = \int_a^{x_1 + \Delta x} f(t) \,dt - \int_a^{x_1} f(t) \,dt. \qquad (1)</math>
| |
| | |
| It can be shown that
| |
| :<math>\int_{a}^{x_1} f(t) \,dt + \int_{x_1}^{x_1 + \Delta x} f(t) \,dt = \int_a^{x_1 + \Delta x} f(t) \,dt. </math>
| |
| :(The sum of the areas of two adjacent regions is equal to the area of both regions combined.)
| |
| Manipulating this equation gives
| |
| :<math>\int_{a}^{x_1 + \Delta x} f(t) \,dt - \int_{a}^{x_1} f(t) \,dt = \int_{x_1}^{x_1 + \Delta x} f(t) \,dt. </math>
| |
| | |
| Substituting the above into (1) results in
| |
| :<math>F(x_1 + \Delta x) - F(x_1) = \int_{x_1}^{x_1 + \Delta x} f(t) \,dt. \qquad (2)</math>
| |
| | |
| According to the [[mean value theorem]] for integration, there exists a real number <math>c(\Delta x)</math> in [''x''<sub>1</sub>, ''x''<sub>1</sub> + Δ''x''] such that
| |
| :<math>\int_{x_1}^{x_1 + \Delta x} f(t) \,dt = f\left(c(\Delta x)\right) \Delta x.</math>
| |
| | |
| To keep the notation simple we will continue writing ''c'' instead of <math>c(\Delta x)</math> but one should keep in mind that ''c'' does depend on <math>\Delta x</math>.
| |
| Substituting the above into (2) we get
| |
| :<math>F(x_1 + \Delta x) - F(x_1) = f(c) \Delta x.</math>
| |
| | |
| Dividing both sides by Δ''x'' gives
| |
| :<math>\frac{F(x_1 + \Delta x) - F(x_1)}{\Delta x} = f(c).</math>
| |
| :The expression on the left side of the equation is Newton's [[difference quotient]] for ''F'' at ''x''<sub>1</sub>.
| |
| | |
| Take the limit as Δ''x'' → 0 on both sides of the equation.
| |
| :<math>\lim_{\Delta x \to 0} \frac{F(x_1 + \Delta x) - F(x_1)}{\Delta x} = \lim_{\Delta x \to 0} f(c). </math>
| |
| | |
| The expression on the left side of the equation is the definition of the derivative of ''F'' at ''x''<sub>1</sub>.
| |
| :<math>F'(x_1) = \lim_{\Delta x \to 0} f(c). \qquad (3) </math>
| |
| | |
| To find the other limit, we use the [[squeeze theorem]]. The number ''c'' is in the interval [''x''<sub>1</sub>, ''x''<sub>1</sub> + Δ''x''], so ''x''<sub>1</sub> ≤ ''c'' ≤ ''x''<sub>1</sub> + Δ''x''.
| |
| | |
| Also, <math>\lim_{\Delta x \to 0} x_1 = x_1</math> and <math>\lim_{\Delta x \to 0} x_1 + \Delta x = x_1.\,</math>
| |
| | |
| Therefore, according to the squeeze theorem,
| |
| :<math>\lim_{\Delta x \to 0} c = x_1.</math>
| |
| | |
| Substituting into (3), we get
| |
| :<math>F'(x_1) = \lim_{c \to x_1} f(c).</math>
| |
| | |
| The function ''f'' is continuous at ''c'', so the limit can be taken inside the function. Therefore, we get
| |
| :<math>F'(x_1) = f(x_1).\ </math>
| |
| which completes the proof.
| |
| | |
| <small>(Leithold ''et al.'', 1996)</small> <small> (a rigorous proof can be found http://www.imomath.com/index.php?options=438)</small>
| |
| | |
| ==Proof of the corollary==
| |
| Suppose ''F'' is an antiderivative of ''f'', with ''f'' continuous on {{nowrap|[''a'', ''b''].}} Let
| |
| | |
| : <math>G(x) = \int_a^x f(t)\, dt</math>.
| |
| | |
| By the ''first part'' of the theorem, we know ''G'' is also an antiderivative of ''f''. It follows by the mean value theorem that there is a number ''c'' such that {{nowrap|''G''(''x'') {{=}} ''F''(''x'') + ''c''}}, for all ''x'' in {{nowrap|[''a'', ''b''].}} Letting {{nowrap|''x'' {{=}} ''a''}}, we have
| |
| | |
| :<math>F(a) + c = G(a) = \int_a^a f(t)\, dt = 0,</math>
| |
| | |
| which means {{nowrap|''c'' {{=}} − ''F''(''a'').}} In other words {{nowrap|''G''(''x'') {{=}} ''F''(''x'') − ''F''(''a'')}}, and so
| |
| | |
| :<math>\int_a^b f(x)\, dx = G(b) = F(b) - F(a).</math>
| |
| | |
| ==Proof of the second part==
| |
| This is a limit proof by [[Riemann integral|Riemann sums]].
| |
| Let ''f'' be (Riemann) integrable on the interval {{nowrap|[''a'', ''b''],}} and let ''f'' admit an antiderivative ''F'' on {{nowrap|[''a'', ''b''].}} Begin with the quantity {{nowrap|''F''(''b'') − ''F''(''a'')}}. Let there be numbers ''x''<sub>1</sub>, ..., ''x''<sub>''n''</sub>
| |
| such that
| |
| | |
| :<math>a = x_0 < x_1 < x_2 < \cdots < x_{n-1} < x_n = b. \, </math>
| |
| | |
| It follows that
| |
| | |
| :<math>F(b) - F(a) = F(x_n) - F(x_0). \, </math>
| |
| | |
| Now, we add each ''F''(''x''<sub>''i''</sub>) along with its additive inverse, so that the resulting quantity is equal:
| |
| | |
| :<math>\begin{align}
| |
| F(b) - F(a)
| |
| &= F(x_n) + [-F(x_{n-1}) + F(x_{n-1})] + \cdots + [-F(x_1) + F(x_1)] - F(x_0) \\
| |
| &= [F(x_n) - F(x_{n-1})] + [F(x_{n-1}) + \cdots - F(x_1)] + [F(x_1) - F(x_0)].
| |
| \end{align}</math>
| |
| | |
| The above quantity can be written as the following sum:
| |
| | |
| :<math>F(b) - F(a) = \sum_{i=1}^n \,[F(x_i) - F(x_{i-1})]. \qquad (1)</math>
| |
| | |
| Next, we employ the [[mean value theorem]]. Stated briefly,
| |
| | |
| Let ''F'' be continuous on the closed interval [''a'', ''b''] and differentiable on the open interval (''a'', ''b''). Then there exists some ''c'' in (''a'', ''b'') such that
| |
| | |
| :<math>F'(c) = \frac{F(b) - F(a)}{b - a}.</math>
| |
| | |
| It follows that
| |
| | |
| :<math>F'(c)(b - a) = F(b) - F(a). \,</math>
| |
| | |
| The function ''F'' is differentiable on the interval {{nowrap|[''a'', ''b''];}} therefore, it is also differentiable and continuous on each interval {{nowrap|[''x''<sub>''i''−1</sub>, ''x''<sub>''i''</sub>]}}. According to the mean value theorem (above),
| |
| | |
| :<math>F(x_i) - F(x_{i-1}) = F'(c_i)(x_i - x_{i-1}). \ </math>
| |
| | |
| Substituting the above into (1), we get
| |
| | |
| :<math>F(b) - F(a) = \sum_{i=1}^n \,[F'(c_i)(x_i - x_{i-1})].</math>
| |
| | |
| The assumption implies <math>F'(c_i) = f(c_i).</math> Also, <math>x_i - x_{i-1}</math> can be expressed as <math>\Delta x</math> of partition <math>i</math>.
| |
| | |
| :<math>F(b) - F(a) = \sum_{i=1}^n \,[f(c_i)(\Delta x_i)]. \qquad (2)</math>
| |
| | |
| [[File:Riemann integral irregular.gif|frame|right|A converging sequence of Riemann sums. The number in the upper left is the total area of the blue rectangles. They converge to the integral of the function.]]
| |
| | |
| We are describing the area of a rectangle, with the width times the height, and we are adding the areas together. Each rectangle, by virtue of the [[Mean Value Theorem]], describes an approximation of the curve section it is drawn over. Also <math>\Delta x_i</math> need not be the same for all values of ''i'', or in other words that the width of the rectangles can differ. What we have to do is approximate the curve with ''n'' rectangles. Now, as the size of the partitions get smaller and ''n'' increases, resulting in more partitions to cover the space, we get closer and closer to the actual area of the curve.
| |
| | |
| By taking the limit of the expression as the norm of the partitions approaches zero, we arrive at the [[Riemann integral]]. We know that this limit exists because ''f'' was assumed to be integrable. That is, we take the limit as the largest of the partitions approaches zero in size, so that all other partitions are smaller and the number of partitions approaches infinity.
| |
| | |
| So, we take the limit on both sides of (2). This gives us
| |
| | |
| :<math>\lim_{\| \Delta x_i \| \to 0} F(b) - F(a) = \lim_{\| \Delta x_i \| \to 0} \sum_{i=1}^n \,[f(c_i)(\Delta x_i)].</math>
| |
| | |
| Neither ''F''(''b'') nor ''F''(''a'') is dependent on <math>||\Delta x_i\|</math>, so the limit on the left side remains {{nowrap|''F''(''b'') − ''F''(''a'').}}
| |
| | |
| :<math>F(b) - F(a) = \lim_{\| \Delta x_i \| \to 0} \sum_{i=1}^n \,[f(c_i)(\Delta x_i)].</math>
| |
| | |
| The expression on the right side of the equation defines the integral over ''f'' from ''a'' to ''b''. Therefore, we obtain
| |
| | |
| :<math>F(b) - F(a) = \int_a^b f(x)\,dx,</math>
| |
| | |
| which completes the proof.
| |
| | |
| It almost looks like the first part of the theorem follows directly from the second. That is, suppose ''G'' is an antiderivative of ''f''. Then by the second theorem, <math>G(x) - G(a) = \int_a^x f(t) \, dt</math>. Now, suppose <math>F(x) = \int_a^x f(t)\, dt\ = G(x) - G(a)</math>. Then ''F'' has the same derivative as ''G'', and therefore {{nowrap|''F''′ {{=}} ''f''}}. This argument only works, however, if we already know that ''f'' has an antiderivative, and the only way we know that all continuous functions have antiderivatives is by the first part of the Fundamental Theorem.<ref>{{Citation |last=Spivak|first=Michael|year=1980|title=Calculus|edition=2nd|publication-place=Houston, Texas|publisher=Publish or Perish Inc.}}</ref>
| |
| For example if {{nowrap|''f''(''x'') {{=}} e<sup>−''x''<sup>2</sup></sup>,}} then ''f'' has an antiderivative, namely
| |
| | |
| :<math>G(x) = \int_0^x f(t) \, dt\,</math>
| |
| | |
| and there is no simpler expression for this function. It is therefore important not to interpret the second part of the theorem as the definition of the integral. Indeed, there are many functions that are integrable but lack antiderivatives that can be written as an [[elementary function]]. Conversely, many functions that have antiderivatives are not Riemann integrable (see [[Volterra's function]]).
| |
| | |
| ==Examples==
| |
| As an example, suppose the following is to be calculated:
| |
| | |
| :<math>\int_2^5 x^2\, dx. </math>
| |
| | |
| Here, <math>f(x) = x^2 \,</math> and we can use <math>F(x) = \frac{x^3}{3} </math> as the antiderivative. Therefore:
| |
| | |
| :<math>\int_2^5 x^2\, dx = F(5) - F(2) = \frac{5^3}{3} - \frac{2^3}{3} = \frac{125}{3} - \frac{8}{3} = \frac{117}{3} = 39.</math>
| |
| | |
| Or, more generally, suppose that
| |
| | |
| :<math>\frac{d}{dx} \int_0^x t^3\, dt </math>
| |
| is to be calculated. Here, <math>f(t) = t^3 \,</math> and <math>F(t) = \frac{t^4}{4} </math> can be used as the antiderivative. Therefore:
| |
| | |
| :<math>\frac{d}{dx} \int_0^x t^3\, dt = \frac{d}{dx} F(x) - \frac{d}{dx} F(0) = \frac{d}{dx} \frac{x^4}{4} = x^3.</math>
| |
| | |
| Or, equivalently,
| |
| | |
| :<math>\frac{d}{dx} \int_0^x t^3\, dt = f(x) \frac{dx}{dx} - f(0) \frac{d0}{dx} = x^3.</math>
| |
| | |
| ==Generalizations==
| |
| We don't need to assume continuity of ''f'' on the whole interval. Part I of the theorem then says: if ''f'' is any [[Lebesgue integration|Lebesgue integrable]] function on {{nowrap|[''a'', ''b'']}} and ''x''<sub>0</sub> is a number in {{nowrap|[''a'', ''b'']}} such that ''f'' is continuous at ''x''<sub>0</sub>, then
| |
| | |
| :<math>F(x) = \int_a^x f(t)\, dt</math>
| |
| | |
| is differentiable for {{nowrap|''x'' {{=}} ''x''<sub>0</sub>}} with {{nowrap|''F''′(''x''<sub>0</sub>) {{=}} ''f''(''x''<sub>0</sub>).}} We can relax the conditions on ''f'' still further and suppose that it is merely locally integrable. In that case, we can conclude that the function ''F'' is differentiable [[almost everywhere]] and {{nowrap|''F''′(''x'') {{=}} ''f''(''x'')}} almost everywhere. On the real line this statement is equivalent to [[Lebesgue differentiation theorem|Lebesgue's differentiation theorem]]. These results remain true for the Henstock–Kurzweil integral, which allows a larger class of integrable functions {{harv|Bartle|2001|loc=Thm. 4.11}}.
| |
| | |
| In higher dimensions Lebesgue's differentiation theorem generalizes the Fundamental theorem of calculus by stating that for almost every ''x'', the average value of a function ''f'' over a ball of radius ''r'' centered at ''x'' tends to ''f''(''x'') as ''r'' tends to 0.
| |
| | |
| Part II of the theorem is true for any Lebesgue integrable function ''f'', which has an antiderivative ''F'' (not all integrable functions do, though). In other words, if a real function ''F'' on {{nowrap|[''a'', ''b'']}} admits a derivative ''f''(''x'') at ''every'' point ''x'' of {{nowrap|[''a'', ''b'']}} and if this derivative ''f'' is Lebesgue integrable on {{nowrap|[''a'', ''b''],}} then
| |
| | |
| :<math>F(b) - F(a) = \int_a^b f(t) \, dt.</math><ref>{{harvnb|Rudin|1987|loc=th. 7.21}}</ref>
| |
| | |
| This result may fail for continuous functions ''F'' that admit a derivative ''f''(''x'') at almost every point ''x'', as the example of the [[Cantor function]] shows. However, if ''F'' is [[Absolute continuity|absolutely continuous]], it admits a derivative ''F′''(''x'') at almost every point ''x'', and moreover ''F′'' is integrable, with {{nowrap|''F''(''b'') − ''F''(''a'')}} equal to the integral of ''F′'' on {{nowrap|[''a'', ''b''].}} Conversely, if ''f'' is any integrable function, then ''F'' as given in the first formula will be absolutely continuous with ''F′'' = ''f'' a.e.
| |
| | |
| The conditions of this theorem may again be relaxed by considering the integrals involved as [[Henstock–Kurzweil integral]]s. Specifically, if a continuous function ''F''(''x'') admits a derivative ''f''(''x'') at all but countably many points, then ''f''(''x'') is Henstock–Kurzweil integrable and {{nowrap|''F''(''b'') − ''F''(''a'')}} is equal to the integral of ''f'' on {{nowrap|[''a'', ''b''].}} The difference here is that the integrability of ''f'' does not need to be assumed. {{harv|Bartle|2001|loc=Thm. 4.7}}
| |
| | |
| The version of [[Taylor's theorem]], which expresses the error term as an integral, can be seen as a generalization of the Fundamental Theorem.
| |
| | |
| There is a version of the theorem for [[complex number|complex]] functions: suppose ''U'' is an open set in '''C''' and {{nowrap|''f'' : ''U'' → '''C'''}} is a function that has a [[holomorphic function|holomorphic]] antiderivative ''F'' on ''U''. Then for every curve {{nowrap|γ : [''a'', ''b''] → ''U'',}} the [[curve integral]] can be computed as
| |
| | |
| :<math>\int_\gamma f(z) \,dz = F(\gamma(b)) - F(\gamma(a)).</math>
| |
| | |
| The fundamental theorem can be generalized to curve and surface integrals in higher dimensions and on [[manifold]]s. One such generalization offered by the [[calculus of moving surfaces]] is the [[time evolution of integrals]]. The most familiar extensions of the Fundamental theorem of calculus in higher dimensions are the [[Divergence theorem]] and the [[Gradient theorem]].
| |
| | |
| One of the most powerful statements in this direction is [[Stokes' theorem]]: Let ''M'' be an oriented [[piecewise]] smooth [[manifold]] of [[dimension]] ''n'' and let <math>\omega</math> be an ''n''−1 form that is a [[compactly supported]] [[differential form]] on ''M'' of class C<sup>1</sup>. If ∂''M'' denotes the [[manifold|boundary]] of ''M'' with its induced [[Orientation (mathematics)|orientation]], then
| |
| | |
| :<math>\int_M d\omega = \oint_{\partial M} \omega.</math>
| |
| | |
| Here ''d'' is the [[exterior derivative]], which is defined using the manifold structure only.
| |
| | |
| The theorem is often used in situations where ''M'' is an embedded oriented submanifold of some bigger manifold on which the form <math>\omega</math> is defined.
| |
| | |
| ==See also==
| |
| {{Portal|Mathematics}}
| |
| * [[Differentiation under the integral sign]]
| |
| | |
| ==Notes==
| |
| <references/>
| |
| | |
| ==References==
| |
| * {{Citation | last1=Apostol | first1=Tom M. | author1-link=Tom M. Apostol | title=Calculus, Vol. 1: One-Variable Calculus with an Introduction to Linear Algebra | publisher=[[John Wiley & Sons]] | location=New York | edition=2nd | isbn=978-0-471-00005-1 | year=1967}}.
| |
| * {{Citation | last1=Bartle | first1=Robert | title=A Modern Theory of Integration | publisher=AMS | isbn=0-8218-0845-1 | year=2001}}.
| |
| * {{citation|last1=Larson|first1=Ron|first2=Bruce H.|last2=Edwards|first3=David E.|last3=Heyd|title=Calculus of a single variable|edition=7th| isbn=978-0-618-14916-2 | publication-place=Boston|publisher=Houghton Mifflin Company|year=2002}}.
| |
| * {{citation|last=Leithold|first=L.|year=1996|title=The calculus of a single variable|edition=6th|publication-place=New York|publisher=HarperCollins College Publishers}}.
| |
| * Malet, A, ''Studies on James Gregorie (1638-1675)'' (PhD Thesis, Princeton, 1989).
| |
| * {{citation|last=Rudin|first=Walter|year=1987|title=Real and Complex Analysis|edition=third|publication-place=New York|publisher=McGraw-Hill Book Co.|isbn=0-07-054234-1 }}
| |
| * {{citation|last=Stewart|first=J.|year=2003|contribution=Fundamental Theorem of Calculus|title=Calculus: early transcendentals|publication-place=Belmont, California|publisher=Thomson/Brooks/Cole}}.
| |
| * {{citation|editor=Turnbull, H. W.|title=The James Gregory Tercentenary Memorial Volume|publication-place=London|year=1939}}.
| |
| * {{Citation |last=Spivak|first=Michael|author1-link=Michael_Spivak|year=1980|title=Calculus|edition=2nd|publication-place=Houston, Texas|publisher=Publish or Perish Inc.}}.
| |
| * {{citation|last1=Courant|first1=Richard|last2=John|first2=Fritz|title=Introduction to Calculus and Analysis|publisher=Springer|year=1965}}.
| |
| | |
| ==External links==
| |
| *[http://mathdl.maa.org/convergence/1/?pa=content&sa=viewDocument&nodeId=388&bodyId=343 James Gregory's Euclidean Proof of the Fundamental Theorem of Calculus] at [http://mathdl.maa.org/convergence/1/ Convergence]
| |
| *[http://school.maths.uwa.edu.au/~schultz/L18Barrow.html Isaac Barrow's proof of the Fundamental Theorem of Calculus]
| |
| *[http://www.imomath.com/index.php?options=438 Fundamental Theorem of Calculus at imomath.com]
| |
| * [http://www.encyclopediaofmath.org/index.php/Newton-Leibniz_Formula Fundamental Theorem of Calculus] at [http://www.encyclopediaofmath.org/ Encyclopedia of Mathematics]
| |
| | |
| {{Fundamental theorems}}
| |
| | |
| {{DEFAULTSORT:Fundamental Theorem Of Calculus}}
| |
| [[Category:Articles containing proofs]]
| |
| [[Category:Fundamental theorems|Calculus]]
| |
| [[Category:Theorems in calculus]]
| |
| [[Category:Theorems in real analysis]]
| |
| | |
| {{Link GA|de}}
| |