Borel conjecture: Difference between revisions

From formulasearchengine
Jump to navigation Jump to search
en>Aleph4
The origin of the conjecture: there is more than one famous Borel
 
en>Giftlite
m −sp
Line 1: Line 1:
Greetings! I am Marvella and I really feel comfortable when individuals use over the counter std test; [http://dore.gia.ncnu.edu.tw/88ipart/node/1326254 read this post here], full title. My day occupation is a meter reader. To gather cash is a factor that I'm totally addicted to. My family life in Minnesota and my family members enjoys it.
In [[mathematics]], a [[sequence]] of [[function (mathematics)|function]]s <math>\{f_{n}\}</math> from a set ''S'' to a metric space ''M'' is said to be '''uniformly Cauchy''' if:
 
* For all <math>\varepsilon > 0</math>, there exists <math>N>0</math> such that for all <math>x\in S</math>: <math>d(f_{n}(x), f_{m}(x)) < \varepsilon</math> whenever <math>m, n > N</math>.
 
Another way of saying this is that <math>d_u (f_{n}, f_{m}) \to 0</math> as <math>m, n \to \infty</math>, where the uniform distance <math>d_u</math> between two functions is defined by
 
:<math>d_{u} (f, g) := \sup_{x \in S} d (f(x), g(x)).</math>
 
== Convergence criteria ==
A sequence of functions {''f''<sub>n</sub>} from ''S'' to ''M'' is '''pointwise''' Cauchy if, for each ''x'' &isin; ''S'', the sequence {''f''<sub>n</sub>(''x'')} is a [[Cauchy sequence]] in ''M''.  This is a weaker condition than being uniformly Cauchy.  Nevertheless, if the metric space ''M'' is [[complete metric space|complete]], then any pointwise Cauchy sequence converges pointwise to a function from ''S'' to ''M''.  Similarly, any uniformly Cauchy sequence will tend [[uniform convergence|uniformly]] to such a function.
 
The uniform Cauchy property is frequently used when the ''S'' is not just a set, but a [[topological space]], and ''M'' is a complete metric space. The following theorem holds:
 
* Let ''S'' be a topological space and ''M'' a complete metric space.  Then any uniformly Cauchy sequence of [[continuous function]]s ''f''<sub>n</sub> : ''S'' &rarr; ''M'' tends [[uniform convergence|uniformly]] to a unique continuous function ''f'' : ''S'' &rarr; ''M''.
 
== Generalization to uniform spaces ==
 
A [[sequence]] of [[function (mathematics)|function]]s <math>\{f_{n}\}</math> from a set ''S'' to a metric space ''U'' is said to be '''uniformly Cauchy''' if:
 
* For all <math>x\in S</math> and for any [[Uniform space|entourage]] <math>\varepsilon</math>, there exists <math>N>0</math> such that <math>d(f_{n}(x), f_{m}(x)) < \varepsilon</math> whenever <math>m, n > N</math>.
 
==See also==
*[[Modes of convergence (annotated index)]]
 
[[Category:Functional analysis]]
[[Category:Convergence (mathematics)]]
 
{{mathanalysis-stub}}

Revision as of 18:11, 18 March 2013

In mathematics, a sequence of functions {fn} from a set S to a metric space M is said to be uniformly Cauchy if:

Another way of saying this is that du(fn,fm)0 as m,n, where the uniform distance du between two functions is defined by

du(f,g):=supxSd(f(x),g(x)).

Convergence criteria

A sequence of functions {fn} from S to M is pointwise Cauchy if, for each xS, the sequence {fn(x)} is a Cauchy sequence in M. This is a weaker condition than being uniformly Cauchy. Nevertheless, if the metric space M is complete, then any pointwise Cauchy sequence converges pointwise to a function from S to M. Similarly, any uniformly Cauchy sequence will tend uniformly to such a function.

The uniform Cauchy property is frequently used when the S is not just a set, but a topological space, and M is a complete metric space. The following theorem holds:

  • Let S be a topological space and M a complete metric space. Then any uniformly Cauchy sequence of continuous functions fn : SM tends uniformly to a unique continuous function f : SM.

Generalization to uniform spaces

A sequence of functions {fn} from a set S to a metric space U is said to be uniformly Cauchy if:

See also

Template:Mathanalysis-stub