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In [[mathematics]], an '''alternating factorial''' is the [[absolute value]] of the [[alternating sum]] of the first ''n'' [[factorial]]s.
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This is the same as their sum, with the odd-indexed factorials multiplied by [[-1 (number)|&minus;1]] if ''n'' is even, and the even-indexed factorials multiplied by &minus;1 if ''n'' is odd, resulting in an alternation of signs of the summands (or alternation of addition and subtraction operators, if preferred). To put it algebraically,
 
:<math>\mathrm{af}(n) = \sum_{i = 1}^n (-1)^{n - i}i!</math>
 
or with the [[recurrence relation]]
 
:<math>\mathrm{af}(n) = n! - \mathrm{af}(n - 1)</math>
 
in which af(1) = 1.
 
The first few alternating factorials are
 
:1, [[1 (number)|1]], [[5 (number)|5]], [[19 (number)|19]], [[101 (number)|101]], 619, 4421, 35899, 326981, 3301819, 36614981, 442386619, 5784634181, 81393657019 {{OEIS|id=A005165}}
 
For example, the third alternating factorial is 1! &minus; 2! + 3!. The fourth alternating factorial is &minus;1! + 2! - 3! + 4! = 19. Regardless of the parity of ''n'', the last (''n''<sup>th</sup>) summand, ''n''!, is given a positive sign, the (''n'' - 1)<sup>th</sup> summand is given a negative sign, and the signs of the lower-indexed summands are alternated accordingly.
 
This pattern of alternation ensures the resulting sums are all positive integers. Changing the rule so that either the odd- or even-indexed summands are given negative signs (regardless of the parity of ''n'') changes the signs of the resulting sums but not their absolute values.
 
Miodrag Zivković proved in 1999 that there are only a finite number of alternating factorials that are also [[prime number]]s, since 3612703 divides af(3612702) and therefore divides af(''n'') for all ''n'' &ge; 3612702. {{As of|2006}}, the known primes and [[probable prime]]s are af(''n'') for {{OEIS|id=A001272}}
:''n'' = 3, 4, 5, 6, 7, 8, 10, 15, 19, 41, 59, 61, 105, 160, 661, 2653, 3069, 3943, 4053, 4998, 8275, 9158, 11164
Only the values up to ''n'' = 661 have been proved prime in 2006. af(661) is approximately 7.818097272875 &times; 10<sup>1578</sup>.
 
==References==
 
* {{MathWorld|urlname=AlternatingFactorial|title=Alternating Factorial}}
 
* Yves Gallot, [http://perso.wanadoo.fr/yves.gallot/papers/lfact.pdf Is the number of primes <math>{1 \over 2}\sum_{i = 0}^{n - 1} i!</math> finite?]
 
* Paul Jobling, [http://listserv.nodak.edu/cgi-bin/wa.exe?A2=ind0411&L=nmbrthry&T=0&P=1106 Guy's problem B43: search for primes of form n!-(n-1)!+(n-2)!-(n-3)!+...+/-1!]
 
[[Category:Integer sequences]]
[[Category:Factorial and binomial topics]]

Revision as of 02:10, 25 February 2014

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